1.7 KiB
1.7 KiB
Thread Hierarchy
thread, block, (cluster), grid
for a two-dimensional block of size
(Dx, Dy), the thread ID of a thread of index(x, y)is(x + y * Dx); for a three-dimensional block of size(Dx, Dy, Dz), the thread ID of a thread of index(x, y, z)is(x + y * Dx + z * Dx * Dy)
SIMT architecture (single-instruction multi-thread)
32 threads as a warp 一个 warp 内 single instruction,不同 thread 若执行的指令流一致,则并行,否则分别执行,因此尽可能保证一个 wrap 内的 thread 执行相同的指令流。Actually in nowadays:
Starting with the NVIDIA Volta architecture, Independent Thread Scheduling allows full concurrency between threads, regardless of warp. threads can now diverge and reconverge at sub-warp granularity.
You can test it by following code:
#include <chrono>
#include <iostream>
#define T 1000000
__global__ void f(float *x) {
int i = blockIdx.x * blockDim.x + threadIdx.x;
for (int t = 0; t < T; t++) {
if (i < (1 << 10)) {
x[i] *= 1.1;
} else {
x[i] += 1;
}
// if (i % 2 == 0) {
// x[i] *= 1.1;
// } else {
// x[i] += 1;
// }
if (x[i] > 1e6) {
x[i] = 1.0;
}
}
}
int main(void) {
int N = 1 << 20;
float *x, *d_x;
x = (float *)malloc(N * sizeof(float));
cudaMalloc(&d_x, N * sizeof(float));
for (int i = 0; i < N; i++) {
x[i] = 1.0f;
}
cudaMemcpy(d_x, x, N * sizeof(float), cudaMemcpyHostToDevice);
auto start = std::chrono::steady_clock::now();
f<<<N / 256, 256>>>(d_x);
auto end = std::chrono::steady_clock::now();
auto elapse = end - start;
std::cout << "time used: " << elapse.count() << " ns" << '\n';
cudaMemcpy(x, d_x, N * sizeof(float), cudaMemcpyDeviceToHost);
cudaFree(d_x);
free(x);
}